Agent (27-06-2012)
For ideal alignment you need the partition to start on a multiple of the erase block size (usually 512kb) as well as the page size (usually 4kb). So Linux and Windows 7 just start at 1mb, which is fine. The old HDD size of multiples of 512 bytes means it meets neither of these. Modern HDDs use 4kb sectors, and so these have to be aligned the same way.
If the boundaries are misaligned you can end up with two cells being erased instead of one, which would seriously reduce the drive's life.
So assuming my Intel drive has a starting offset of 105906176 which divided by 4096 gives a mammoth number... what do I do?
Originally Posted by Advice Trinity by Knoxville
Zak33 (19-06-2012)
thats good.. cos it flies and always has
Originally Posted by Advice Trinity by Knoxville
Ok i will give a bash !!!
The SSD image that is
many thanks mateys
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