Doesn't it depend on whether we are talking about real numbers? (this is really stretching my maths...)
Wikipedia (and yes I know!) states the following:
In mathematics, the repeating decimal 0.999… which may also be written as 0.\bar{9} , 0.\dot{9} or 0.(9)\,\! denotes a real number equal to one. In other words, the notations 0.999… and 1 represent the same real number. This equality has long been accepted by professional mathematicians and taught in textbooks. Proofs have been formulated with varying degrees of mathematical rigour, taking into account preferred development of the real numbers, background assumptions, historical context, and target audience.
Let x = 0.9 (rec)
10x = 9.9 (rec)
10x - x = 9.9 (rec) - 0.9 (rec) = 9
9x = 9
x = 1
=> 0.9 (rec) = 1
QED.
Edit: interesting reading.....
https://nrich.maths.org/discus/messa...613/68880.html
https://nrich.maths.org/discus/messa...613/67006.html
Last edited by LWA; 07-10-2009 at 03:43 PM.
heh, nerds!
just joking, good luck with your question mate
nice findings..
but b is right..
given in the example in the sites, :
1/9=0.11111111
3/9=0.33333333
6/9=.666666666
therefore 9/9=0.99999999
also 9/9 also =1..
this is just part of the fun i picked up in my juniors, which something i cannot forget trying to disproof.. lol... those were happy days...
I'd like to think that with an O level in Maths (grade A, done with mild hangovers) and a total Ungraded in Maths A level (how on earth were those two levels of exam SOOOO far apart) I'd like to think I have totally forgotten how to factoris/ze, with an S or a Z.
But I can cheer you on towards finding the result
Originally Posted by Advice Trinity by Knoxville
I'd like to think I knew the answer, but I don't, because it's been ages since I last studied or used maths beyond the basic stuff.
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This is bunny and friends. He is fed up waiting for everyone to help him out, and decided to help himself instead!
Ask Wolfram Alpha
http://www.wolframalpha.com/input/?i=-2x^2%2B8x%2B4
(edit forum crapping up the link. paste "-2x^2+8x+4" into search box)
he knows.
throw new ArgumentException (String, String, Exception)
The purpose of factorisation is to simply isolate the roots of the characteristic equation, i.e. (x+2)(x+2) = 0 essentially means double roots at x = -2
The only solution as I see it is x = -0.45 (to 2 d.p.) and x = 4.45; I simply used the formula x = [-b±(b^2-4ac)^0.5]/2a
I remember a simple rule to find if a quadratic equation can be easily factorised. If the result of
(b^2-4ac)^0.5 is a perfect square it'll work out; else you have to use the equation.
edit: I tried TheAnimus's suggestion, it works quite nicely!
http://www.wolframalpha.com/input/?i=-2x^2%2B8x%2B4
x = 2 - (6)^0.5 and x = 2 + (6)^0.5 which is the same result as the decimal values I gave above.
Last edited by bsodmike; 07-10-2009 at 07:03 PM.
irth1ing (12-10-2009)
I got an A at GCSE, a C at A Level and an E at A level further maths...
and I can't remember how to complete the square
I do remember learning it though. I also recently realised that I can't remember how Differentiation or integration any more. I really hope one of my kids does A level maths.
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