Originally Posted by
Timo
It's not quite as simple as that.
Imagine a disc (platter) spinning at a given speed, like old vinyl records. At the edge of the disc, the circumference is greater, meaning more data can be stored, written and read within one single revolution. However, the further in to the centre of the disc the circumference decreases, so less data can be held and read/written during a full revolution. In actual fact, at the middle of the disc, you can store only half of the data that you can store on the outer edge. Or, to put it another way, the effective speed that data can be read/written at the inner-most of the disc is halved that of data on the outer edge.
So let's take an 80GB hard-disk. When you have added, say, 79GB of data, so that it's nearly full, the hard-drive performance for the data lying at the inner-most of the disc is halved, as the circumference is at its smallest.
Now let's take a 500GB hard-disk. If you added 79GB of data to it, as above, the disc would be only about a sixth full, but the data is nowhere near the inner-most of the disc yet, therefore performance is not compromised as much as it would be on a 80GB drive. Only when you have added 499GB of data to it would the performance for the data lying at the innermost part of the disc would be halved.
In other words, it would take 500GB of data on a 500GB disk for performance of the data lying at the inner most of the disc to be halved. But it would take only 80GB on an 80GB disk for data lying at the inner-most part of the disc for the performance to be halved. So if you had just 80GB on a 500GB disk, the performance of data lying at the inner-most part wouldn't be at all as bad as 80GB being on an 80GB disk. It would be significantly faster.