I picked up a couple of those HP n54L Microservers while the cashback offer was on and was thinking about stuffing one full of RAM and HDDs and running it as a freeNAS appliance.
I think technically the servers can run 6 disks, but only have internal space for 5 (4 cold swaps and the ODD bay), so my plan was to stick 5x WD Red 3TBs in there.
I have read a little about RAID-Z and think that this is the way I want to go. The problem is I'm not totally sure how much resilience/storage I will have available in the various RAID-Z configurations, mainly due to not being sure how the parity drives work.
Using the Freenas hardware recoomendations wiki (http://doc.freenas.org/index.php/Har...ecommendations), this is what I've arrived at - I think my Googling is hampered by the number 5 as most results are about "RAID5"..
Assuming 3TB drives (and ignoring the "actual" capacity being lower for simplicity)
RAID-Z1 - 4x data drives + 1 parity drive = 12TB storage and resilience to 1 disk failing.
RAID-Z2 - 2x data drives + 2 parity drives = 6TB storage and resilience to 2 disks failing.
RAID-Z2 - 4x data drives + 2 parity drives = 12TB storage and resilience to 2 disks failing. The docs say RAID-Z2 needs 4, 6 or 10 drives, so going with 6 which is going to be tricky in the n54l.
Am I right in assuming that for RAID-Z1 there is only ever 1 parity drive, and RAID-Z2 there are 2? Or does the number increase as more data drives are added?
So, does everything seem about right, or have I got a bit mixed up in my assumptions?