I am afraid that even after some really helpful advice about RAM speeds, I am still somewhat confused about the maths formula, so maybe if I put down the specifics, some kind sole (kalniel?) may provide the numbers / formula / explanation. I have a real mental block with this, simple as it seems to be for everyone else!
I have an E6700 which at stock runs on a multiplier of 10 and has a CPU clock speed (aka FSB or frequency) of 266 MHz and so 10*266 = 2.67 GHz CPU Speed.
To run this at full speed I understand that I need PC 4300 running at 533 MHz (2*266) – so where does the ‘quad pumped’ bit come in, which I understood meant an FSB of 1064 (4*266)?
I plan to overclock this E6700 and have a target of 3.66GHz, which I understand is quite achievable, by raising the CPU Clock frequency from 266 to 366, increasing the Memory voltage to (2.0v for Corsair PC8500), increasing the CPU VCore to 1.35, plus a few other settings.
What I don’t understand is what speed memory I now need, is this 366*2 = 732 so PC6400 (800 MHz) is the minimum with RAM running synchronously? - but if I run a 5:4 RAM:CPU clock ratio (732/4*5 = 915MHz) then I need PC8000 (1000 MHz) or even PC8500 (1066Mhz), or if I have PC6400 RAM that overclocks well, I have to increase the RAM Voltage and maybe loosen the RAM timings and set the DRAM Frequency as “DDR2-PC1098” in the BIOS?
Of course I may ‘only’ get to a CPU clock of 350….. or less, but I am not sure I understand what RAM timings this overclocking produces. If my numbers in the preceding paragraph are correct, maybe I have sort of stumbled on it, but if they are not correct I am clearly ob the wrong track.